Biochemistry drawing a enediol

A certain aldose is added to an aqueous sodium hydroxide solution. After equilibrium is reached it is found that there are 3 open chain sugars in the solution. It is believed that the original aldose tautomerizes to the enediol which then tautomerizes back to a carbonyl containing open chain sugar. One of the three is L-xylulose.

A) Select the other two isomers.

[INPUT]D-gulose[INPUT]D-allose[INPUT]D-mannose[INPUT]D-galactose[INPUT]D-idose[INPUT]D-lyxose[INPUT]D-xylose[INPUT]D-glucose[INPUT]D-altrose[INPUT]D-talose[INPUT]D-arabinose[INPUT]D-ribose[INPUT]L-gulose[INPUT]L-allose[INPUT]L-mannose[INPUT]L-galactose[INPUT]L-idose[INPUT]L-lyxose[INPUT]L-xylose[INPUT]L-glucose[INPUT]L-altrose[INPUT]L-talose[INPUT]L-arabinose[INPUT]L-ribose[IMG: Correct: Your answer is correct.]

B) Select all of the isomer designations that apply to the isomeric relationship between the two sugars you selected in part A.

[INPUT]constitutional isomers[INPUT]epimers[INPUT]conformational isomers[INPUT]tautomers[INPUT]enantiomers[INPUT]stereoisomers[INPUT]diastereomers[IMG: Correct: Your answer is correct.]

C) Select all of the isomer designations that apply to the isomeric relationship between one of the sugars you selected in part A and L-xylulose.

[INPUT]conformational isomers[INPUT]tautomers[INPUT]enantiomers[INPUT]constitutional isomers[INPUT]epimers[INPUT]stereoisomers[INPUT]diastereomers[IMG: Correct: Your answer is correct.]

D) Draw the enediol that is believed to be the intermediate. /Note: I’ve coded the answer key to accept either the E or Z isomer.

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